document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22528>Question 22528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Texas ranch is in the shape of a square 60 miles on each side. If the ranch house is at the exact center of the square, how far is it from the house to any corner of the property? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11043 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use Pythagoras to find the length of a diagonal:<BR>\n" );
document.write( "  60^2 + 60^2 = (diagonal)^2<BR>\n" );
document.write( "You should get diagonal = 60(sqrt 2)\r<BR>\n" );
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document.write( "The house is half-way along the diagonal or<BR>\n" );
document.write( "30(sqrt2) from each corner of the property.\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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