document.write( "Question 150465: I haven't been able to figure out the answer. How do I solve the following problem:
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Algebra.Com's Answer #110429 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming that you mean \"x%5E2%2B3x%2B1=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x%2B1=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%283%29+%2B-+sqrt%28+%283%29%5E2-4%281%29%281%29+%29%29%2F%282%281%29%29\" Plug in \"a=1\", \"b=3\", and \"c=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+9-4%281%29%281%29+%29%29%2F%282%281%29%29\" Square \"3\" to get \"9\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+9-4+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%281%29\" to get \"4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+5+%29%29%2F%282%281%29%29\" Subtract \"4\" from \"9\" to get \"5\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+5+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3%2Bsqrt%285%29%29%2F%282%29\" or \"x+=+%28-3-sqrt%285%29%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So our answers are \"x+=+%28-3%2Bsqrt%285%29%29%2F%282%29\" or \"x+=+%28-3-sqrt%285%29%29%2F%282%29\" \r
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\n" ); document.write( "\n" ); document.write( "which approximate to \"x=-0.382\" or \"x=-2.618\"
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