document.write( "Question 150312: Please help me write (3-2i) in polar form.
\n" ); document.write( "Here are the choices:
\n" ); document.write( "1. sqrt13(cos 33.7 degrees + i sin 33.7 degrees)
\n" ); document.write( "2. sqrt5(cos 326.3 degrees + i sin 326.3 degrees)
\n" ); document.write( "3. sqrt5(cos 33.7 degrees + i sin 33.7 degrees)
\n" ); document.write( "4. sqrt13(cos 326.3 degrees + i sin 326.3 degrees)
\n" ); document.write( "Thanks, Tami
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Algebra.Com's Answer #110422 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"abs%283-2i%29=sqrt%283%5E2%2B2%5E2%29=sqrt%2813%29\"
\n" ); document.write( "\"3-2i=sqrt%2813%29%283%2Fsqrt%2813%29-2i%2Fsqrt%2813%29%29\"
\n" ); document.write( "\"cos%28A%29=3%2Fsqrt%2813%29\"
\n" ); document.write( "\"A=33.7\" or \"A=360-33.7=326.3\"
\n" ); document.write( "Since, 3-2i is in the 4th quadrant, then A=326.3
\n" ); document.write( "\"3-2i=sqrt%2813%29%28cos%28326.3%29%2Bi%2Asin%28326.3%29%29\"
\n" ); document.write( "Looks like #4.
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