document.write( "Question 150457: Solve for k
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Algebra.Com's Answer #110411 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%288a%5E2b%5E3%29%2F%283k%29=4a\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"8a%5E2b%5E3=4a%283k%29\" Multiply both sides by \"3k\".\r
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\n" ); document.write( "\n" ); document.write( "\"8a%5E2b%5E3=12ak\" Multiply 4 and 3 to get 12\r
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\n" ); document.write( "\n" ); document.write( "\"8a%5E2b%5E3=12ak\" Divide both sides by \"12a\".\r
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\n" ); document.write( "\n" ); document.write( "\"%288a%5E2b%5E3%29%2F%2812a%29=k\" Divide both sides by \"12a\".\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2A2%2A2%2Aa%2Aa%2Ab%5E3%29%2F%2812a%29=k\" Expand \"8a%5E2\" to get \"2%2A2%2A2%2Aa%2Aa\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2A2%2A2%2Aa%2Aa%2Ab%5E3%29%2F%282%2A2%2A3%2Aa%29=k\" Expand \"12a\" to get \"2%2A2%2A3%2Aa\"\r
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\n" ); document.write( "\n" ); document.write( " Highlight the common terms.\r
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\n" ); document.write( "\n" ); document.write( " Cancel out the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%282ab%5E3%29%2F%283%29=k\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"k=%282ab%5E3%29%2F%283%29\"
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