document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22634>Question 22634</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi im in 8th grade and i need help with linear equations can you help me understand them and can you tell me how to do them heres one 6(8+3a)=-2(a-4) thankyou </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11041 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6(8+3a)=-2(a-4)<BR>\n" );
document.write( "48+18a=-2a+8<BR>\n" );
document.write( "40 =-20a<BR>\n" );
document.write( "a = -2\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );