document.write( "Question 150339: Write the equation of a line in standard form, passing through (-2,-3) and parallel to a line with the equation 3x-y=2 \n" ); document.write( "
Algebra.Com's Answer #110406 by ankor@dixie-net.com(22740)\"\" \"About 
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Write the equation of a line in standard form, passing through (-2,-3) and parallel to a line with the equation 3x-y=2
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\n" ); document.write( "Since they are parallel both lines will have the same slope
\n" ); document.write( "Find the slope from the given equation, put it in the slope/intercept form
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\n" ); document.write( "3x - y = 2
\n" ); document.write( "-y = -3x + 2
\n" ); document.write( "y = +3x - 2; y has to be positive, multiply by -1
\n" ); document.write( "the slope: m = 3
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\n" ); document.write( "Find the line with coordinates -2,-3 and m=3;
\n" ); document.write( "use point slope formula y - y1 = m(x-x1)
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\n" ); document.write( "y -(-3) = 3(x - (-2))
\n" ); document.write( "y + 3 = 3(x + 2)
\n" ); document.write( "y + 3 = 3x + 6
\n" ); document.write( "y = 3x + 6 - 3
\n" ); document.write( "y = 3x + 3
\n" ); document.write( "Standard form
\n" ); document.write( "-3x + y = 3
\n" ); document.write( "or
\n" ); document.write( "3x - y = -3
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