document.write( "Question 150442: The following appears to prove that any two numbers are equal. Obviously it is wrong; can you spot the flaw? \r
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document.write( "Let a and b be any two different numbers. Define x as the difference between them:\r
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document.write( "x = b - a
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document.write( "Multiply both sides of the equation by (b-a):
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document.write( "x(b – a) = (b – a)(b – a)
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document.write( "bx – ax = b^2 – 2ab + a^2
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document.write( "Add –bx+ab-a^2 to both sides and simplify:
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document.write( "bx – ax – bx + ab – a^2 = b^2 – 2ab + a^2 – bx + ab – a^2
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document.write( "bx – bx – ax + ab – a^2 = –bx + b^2 – 2ab + ab + a^2 – a^2
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document.write( "–ax + ab – a^2 = –bx + b^2 – ab
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document.write( "Both sides of this equation have a common factor:
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document.write( "a(–x + b – a) = b(–x + b – a)
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document.write( "Divide both sides by (-x+b-a):
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document.write( "a(–x + b – a)/-x + b-a = b(–x + b – a)/ -x + b - a
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document.write( "a = b
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document.write( "What was my mistake?\r
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Algebra.Com's Answer #110388 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! You said \"Divide both sides by (-x+b-a)\"\r \n" ); document.write( "\n" ); document.write( "But what is x? \n" ); document.write( "x = b-a\r \n" ); document.write( "\n" ); document.write( "So what is (-x + b -a)? \n" ); document.write( "(-b + a + b - a) = 0\r \n" ); document.write( "\n" ); document.write( "You can make 'anything' happen if you allow division by zero. Which is why division by zero is undefined.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |