document.write( "Question 150429: Please help me with this algebra problem. It states:
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document.write( "If a probasketball plaer has a vertical leap of about 25 inches, what is his hang time? Use the hang-time function V=48T^2.\r
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document.write( "Please help solve. Thanks. \n" );
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Algebra.Com's Answer #110376 by nerdybill(7384) You can put this solution on YOUR website! Your problem gives you: \n" ); document.write( "V=48T^2 \n" ); document.write( "where \n" ); document.write( "V is the \"vertical leap\" \n" ); document.write( "T is the \"hang time\" \n" ); document.write( ". \n" ); document.write( "Now, they want to know the \"hang time\" if the \"vertical leap\" is 25 inches. So, plug in the given value (V) and solve for T: \n" ); document.write( "V=48T^2 \n" ); document.write( "25=48T^2 \n" ); document.write( "25/48 = T^2 \n" ); document.write( "0.521 = T^2 \n" ); document.write( "sqrt(0.521) = T \n" ); document.write( "0.722 seconds = T \n" ); document.write( " |