document.write( "Question 150363: Use the Gauss - Jordan method to solve the system of equations.\r
\n" ); document.write( "\n" ); document.write( " 3x +12y =-12
\n" ); document.write( " -6x-17y = 3\r
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\n" ); document.write( "\n" ); document.write( "Here is my work, but i'm not sure if it's correct\r
\n" ); document.write( "\n" ); document.write( "[3 12 |-12] 1/3 R1
\n" ); document.write( "[-6 -17 |3] 2 R1 + R2 \r
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\n" ); document.write( "\n" ); document.write( "Turns to [1 4 |-4] -4 R2+R1
\n" ); document.write( " [0 7 |-27] 1/7
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\n" ); document.write( "\n" ); document.write( "Turns to [1 0 |11 3/7] X= 11 3/7
\n" ); document.write( " [0 1 | -3 6/7] Y= -3 6/7\r
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\n" ); document.write( "\n" ); document.write( "answer {(11 3/7, -3 6/7)}
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Algebra.Com's Answer #110373 by mgmoeab(37)\"\" \"About 
You can put this solution on YOUR website!
let see:
\n" ); document.write( "+3x+12y|-12
\n" ); document.write( "-6x-17y|+03\r
\n" ); document.write( "\n" ); document.write( "Coefficient matrix
\n" ); document.write( "+3+12|-12
\n" ); document.write( "-6-17|+03\r
\n" ); document.write( "\n" ); document.write( "+1+4|-4 -----|> 1/3R1
\n" ); document.write( "*0+7|-21 -----|> 6R1+R2\r
\n" ); document.write( "\n" ); document.write( "+1+4|-4
\n" ); document.write( "*0+1|-3 -----|> 1/7R2\r
\n" ); document.write( "\n" ); document.write( "REDUCED TO:
\n" ); document.write( "+1*0|+8 -----|> -4R2+R1
\n" ); document.write( "*0+1|-3 \r
\n" ); document.write( "\n" ); document.write( "SOLUTION:
\n" ); document.write( "3(8)+12(-3)=-12
\n" ); document.write( "-6(8)-17(-3)=3
\n" ); document.write( "X= 8, Y=-3
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