document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=150406>Question 150406</A>: <I><SPAN STYLE=\"word-break: break-all;\"> richie is now 14 y.o., and aimee is 26 y.o. in how many years will the age of richie be 2/3 of aimee's age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #110355 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=110355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = yrs when richie is 2/3's aimee's age<BR>\n" );
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document.write( "14+x = (2/3)(26+x)<BR>\n" );
document.write( "42+3x = 2(26+x)<BR>\n" );
document.write( "42+3x = 52+2x<BR>\n" );
document.write( "42+x = 52<BR>\n" );
document.write( "x = 10 years<BR>\n" );
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