document.write( "Question 150401: Can you please help me solve this problems:\r
\n" ); document.write( "\n" ); document.write( "1.) Erwin is 5 times older than john and John is twice as old as his sister, Alice. In 2 years time, the sum of their ages will be 58. How old is john now?\r
\n" ); document.write( "\n" ); document.write( "2.) John is twice as old as his friend peter. Peter is 5 years older than Alice. In 5 years, John will be three times as old as Alice. How old is Peter?\r
\n" ); document.write( "\n" ); document.write( "3.) Reggie is 5 years older than Lani. Five years ago, the sum of their ages is 25. How old are they now?
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Algebra.Com's Answer #110338 by mangopeeler07(462)\"\" \"About 
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1. Erwin is 5 times older than john and John is twice as old as his sister, Alice.\r
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\n" ); document.write( "\n" ); document.write( "Erwin=5j
\n" ); document.write( "John=j; 2a
\n" ); document.write( "Alice=a; 1/2j\r
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\n" ); document.write( "\n" ); document.write( "Use j, since all of the people can be expressed in terms of j.
\n" ); document.write( "In 2 years time, the sum of their ages will be 58.\r
\n" ); document.write( "\n" ); document.write( "5j+2+j+2+1/2j+2=58\r
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\n" ); document.write( "\n" ); document.write( "Combine like terms
\n" ); document.write( "6.5j+6=58\r
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\n" ); document.write( "\n" ); document.write( "Subtract 6
\n" ); document.write( "6.5j=52\r
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\n" ); document.write( "\n" ); document.write( "Divide by 6.5
\n" ); document.write( "j=8\r
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\n" ); document.write( "\n" ); document.write( "Erwin=5(8)
\n" ); document.write( "John=(8)
\n" ); document.write( "Alice=1/2(8)\r
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\n" ); document.write( "\n" ); document.write( "5(8)+(8)+1/2(8)+6=58
\n" ); document.write( "40+8+4+6=58\r
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\n" ); document.write( "\n" ); document.write( "Erwin=40
\n" ); document.write( "*John=8*
\n" ); document.write( "Alice=4
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\n" ); document.write( "2. John is twice as old as his friend peter. Peter is 5 years older than Alice.\r
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\n" ); document.write( "\n" ); document.write( "John=2p
\n" ); document.write( "Peter=p; a+5
\n" ); document.write( "Alice=p-5\r
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\n" ); document.write( "\n" ); document.write( "Use p as the variable.
\n" ); document.write( "In 5 years, John will be three times as old as Alice.
\n" ); document.write( "2p+5=3(p-5+5)\r
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\n" ); document.write( "\n" ); document.write( "Simplify
\n" ); document.write( "2p+5=3p\r
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\n" ); document.write( "\n" ); document.write( "Subtract 2p from both sides
\n" ); document.write( "5=p\r
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\n" ); document.write( "\n" ); document.write( "John=2(5)
\n" ); document.write( "Peter=(5)
\n" ); document.write( "Alice=(5)-5\r
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\n" ); document.write( "\n" ); document.write( "John=10
\n" ); document.write( "*Peter=5*
\n" ); document.write( "Alice=0
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\n" ); document.write( "3. Reggie is 5 years older than Lani.\r
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\n" ); document.write( "\n" ); document.write( "Reggie=L+5
\n" ); document.write( "Lani=L\r
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\n" ); document.write( "\n" ); document.write( "Five years ago, the sum of their ages is 25.
\n" ); document.write( "(L+5)-5+(L)-5=25\r
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\n" ); document.write( "\n" ); document.write( "L+L-5=25
\n" ); document.write( "2L-5=25
\n" ); document.write( "2L=30
\n" ); document.write( "L=15\r
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\n" ); document.write( "\n" ); document.write( "Reggie=(15)+5
\n" ); document.write( "Lani=(15)\r
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\n" ); document.write( "\n" ); document.write( "Reggie=20
\n" ); document.write( "Lani=15
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