document.write( "Question 150401: Can you please help me solve this problems:\r
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document.write( "1.) Erwin is 5 times older than john and John is twice as old as his sister, Alice. In 2 years time, the sum of their ages will be 58. How old is john now?\r
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document.write( "2.) John is twice as old as his friend peter. Peter is 5 years older than Alice. In 5 years, John will be three times as old as Alice. How old is Peter?\r
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document.write( "3.) Reggie is 5 years older than Lani. Five years ago, the sum of their ages is 25. How old are they now? \n" );
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Algebra.Com's Answer #110338 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! 1. Erwin is 5 times older than john and John is twice as old as his sister, Alice.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Erwin=5j \n" ); document.write( "John=j; 2a \n" ); document.write( "Alice=a; 1/2j\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use j, since all of the people can be expressed in terms of j. \n" ); document.write( "In 2 years time, the sum of their ages will be 58.\r \n" ); document.write( "\n" ); document.write( "5j+2+j+2+1/2j+2=58\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Combine like terms \n" ); document.write( "6.5j+6=58\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 6 \n" ); document.write( "6.5j=52\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide by 6.5 \n" ); document.write( "j=8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Erwin=5(8) \n" ); document.write( "John=(8) \n" ); document.write( "Alice=1/2(8)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5(8)+(8)+1/2(8)+6=58 \n" ); document.write( "40+8+4+6=58\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Erwin=40 \n" ); document.write( "*John=8* \n" ); document.write( "Alice=4 \n" ); document.write( "---------------------------------------------------------------------------- \n" ); document.write( "2. John is twice as old as his friend peter. Peter is 5 years older than Alice.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John=2p \n" ); document.write( "Peter=p; a+5 \n" ); document.write( "Alice=p-5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use p as the variable. \n" ); document.write( "In 5 years, John will be three times as old as Alice. \n" ); document.write( "2p+5=3(p-5+5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify \n" ); document.write( "2p+5=3p\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 2p from both sides \n" ); document.write( "5=p\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John=2(5) \n" ); document.write( "Peter=(5) \n" ); document.write( "Alice=(5)-5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John=10 \n" ); document.write( "*Peter=5* \n" ); document.write( "Alice=0 \n" ); document.write( "------------------------------------------------------------------------- \n" ); document.write( "3. Reggie is 5 years older than Lani.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Reggie=L+5 \n" ); document.write( "Lani=L\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Five years ago, the sum of their ages is 25. \n" ); document.write( "(L+5)-5+(L)-5=25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L+L-5=25 \n" ); document.write( "2L-5=25 \n" ); document.write( "2L=30 \n" ); document.write( "L=15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Reggie=(15)+5 \n" ); document.write( "Lani=(15)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Reggie=20 \n" ); document.write( "Lani=15 \n" ); document.write( " |