document.write( "Question 150376: x-3y=7
\n" ); document.write( "2x-5y=13
\n" ); document.write( "solve by substitution
\n" ); document.write( "

Algebra.Com's Answer #110334 by stanbon(75887)\"\" \"About 
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x-3y=7
\n" ); document.write( "2x-5y=13
\n" ); document.write( "solve by substitution
\n" ); document.write( "-------------
\n" ); document.write( "Solve the 1st for \"x\":
\n" ); document.write( "x = 3y+7
\n" ); document.write( "Substitute that into the 2nd to get:
\n" ); document.write( "2(3y+7) - 5y = 13
\n" ); document.write( "y = -1
\n" ); document.write( "------------
\n" ); document.write( "Substitute into x = 3y+7 to solve for \"y\":
\n" ); document.write( "x = 3*-1+7
\n" ); document.write( "x = 4
\n" ); document.write( "-------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );