document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=150309>Question 150309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a force of 3600 pounds is needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet what force would be required to keep the same car from skidding on a curve of radius 570 feet at 50 mph? Round your answer to the nearest pound of force? \r<BR>\n" );
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document.write( "I don't know what formula that would be to use... I don't know how to approach this task...  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #110291 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=110291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a formula is not needed __ this is a proportional problem __ k is the constant of proportionality\r<BR>\n" );
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document.write( "3600=[k*1800*20^2]/600 __ 3600=k*1200 __ dividing by 1200 __ 3=k\r<BR>\n" );
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document.write( "f=[3*1800*50^2]/570 __ f=23684 </SPAN>\n" );
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