document.write( "Question 150300: The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a force of 3600 pounds is needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet what force would be required to keep the same car from skidding on a curve of radius 570 feet at 50 mph? Round your answer to the nearest pound of force? \r
\n" ); document.write( "\n" ); document.write( "I don't know the formular for this one and thus don't know how to solve it.
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Algebra.Com's Answer #110274 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
For problems describing variation of one thing compared to something else, you can derive the formula yourself.
\n" ); document.write( "Here's how:
\n" ); document.write( "Let F = force, W = car's weight, S = car's speed, and R = radius of curvature.
\n" ); document.write( "You can write:
\n" ); document.write( "\"F+=+kWS%5E2%2FR\" The force, F, varies jointly (and directly) as the the car's weight, W, and the square of the car's speed, S, so W and S go on top and inversely as the radius, R, of the curve, so R goes on the bottom.
\n" ); document.write( "Note that since this is variation problem, it is not correct to say that the force, F, equals the right side, so you must use a constant of variation, and that's the k in the formula.
\n" ); document.write( "Now you can substitute the given numbers for F =(3600 pounds), W = (1800 pounds), and S = (20 mph), and (R = 600 ft.) to find the value of k.
\n" ); document.write( "\"3600+=+k%281800%29%2820%29%5E2%2F600\"
\n" ); document.write( "\"3600+=+k%281800%29%28400%29%2F600\" Simplify.
\n" ); document.write( "\"3600+=+k%281200%29\" Divide both sides by 1200.
\n" ); document.write( "\"3+=+k\", so now the formula becomes:
\n" ); document.write( "\"F+=+3WS%5E2%2FR\"
\n" ); document.write( "Now substitute the second set of numbers for W = 1800, S = 50mph, and R = 570 ft.
\n" ); document.write( "\"F+=+3%281800%29%2850%29%5E2%2F570\"
\n" ); document.write( "\"F+=+3%281800%29%282500%29%2F570\"
\n" ); document.write( "\"F+=+23684\"pounds of force.
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