document.write( "Question 150300: The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a force of 3600 pounds is needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet what force would be required to keep the same car from skidding on a curve of radius 570 feet at 50 mph? Round your answer to the nearest pound of force? \r
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document.write( "I don't know the formular for this one and thus don't know how to solve it. \n" );
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Algebra.Com's Answer #110274 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! For problems describing variation of one thing compared to something else, you can derive the formula yourself. \n" ); document.write( "Here's how: \n" ); document.write( "Let F = force, W = car's weight, S = car's speed, and R = radius of curvature. \n" ); document.write( "You can write: \n" ); document.write( " \n" ); document.write( "Note that since this is variation problem, it is not correct to say that the force, F, equals the right side, so you must use a constant of variation, and that's the k in the formula. \n" ); document.write( "Now you can substitute the given numbers for F =(3600 pounds), W = (1800 pounds), and S = (20 mph), and (R = 600 ft.) to find the value of k. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now substitute the second set of numbers for W = 1800, S = 50mph, and R = 570 ft. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |