document.write( "Question 150247: Luisa is 5 years younger than her sister Sigrid,8 years from now she will be four-fifths as old as her sister will be then. How old is each now?
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Algebra.Com's Answer #110243 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! ----\"Luisa is 5 years younger than her sister Sigrid\"----\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Luisa=L \n" ); document.write( "Sigrid=L+5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----\"8 years from now she will be four-fifths as old as her sister will be then\"----\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L+8=4/5(L+5+8)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Combine like terms on the right side \n" ); document.write( "L+8=4/5(L+13)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distribute on the right side \n" ); document.write( "L+8=4/5L+10.4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 8 from both sides \n" ); document.write( "L=4/5L+2.4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 4/5L from both sides \n" ); document.write( "1/5L=2.4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply both sides by 5 \n" ); document.write( "L=12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Luisa=L \n" ); document.write( "Sigrid=L+5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----\"How old is each now?\"----\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Louisa=12 \n" ); document.write( "Sigrid=17 \n" ); document.write( " |