document.write( "Question 150245This question is from textbook Elementary and Intermediate Algebra
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document.write( ": The members of a flying club plan to share equally the cost of a $200,000 airplane. The members want to find five more people to join the club so that the cost per person will decrease by $2000. How many members are currently in the club? \n" );
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Algebra.Com's Answer #110240 by mangopeeler07(462) ![]() You can put this solution on YOUR website! constant=cost in thousands *(so you have less zeros and it looks less confusing) \n" ); document.write( "y=number of people \n" ); document.write( "x=price per person\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "200/y=x \n" ); document.write( "(200/y+5)=x-2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute x \n" ); document.write( "(200/y+5)=(200/y)-2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Common denominator on the right side=y \n" ); document.write( "200/y+5=200/y - 2y/y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Combine like terms on the right side \n" ); document.write( "200/y+5=200-2y/y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cross multiply \n" ); document.write( "200y=(y+5)(-2y+200)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "FOIL the right side \n" ); document.write( "200y=-2y^2+190y+1000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 200y from both sides \n" ); document.write( "0=-2y^2-10y+1000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factor out a negative 2 \n" ); document.write( "0=-2(y^2+5y-500)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factor \n" ); document.write( "0=-2(y+25)(y-20)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for y \n" ); document.write( "y+25=0 \n" ); document.write( "y=-25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y-20=0 \n" ); document.write( "y=20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You got two solutions, but since y=number of people, and the amount of people cannot be negative, you know that y=20 is your answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "# of current members: 20 \n" ); document.write( " |