document.write( "Question 150241: Pipe A fills a 50-liter tank at a rate of 15 liters per hour. Pipe B fills the same tank at a rate of 10 liters per hour. Pipe A runs alone for 100 minutes then the two of them together finish filling up the tank. How long does the whole operation take?\r
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document.write( "The answer is 160 minutes, but I have no idea how to arrive at this answer. Thank you! \n" );
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Algebra.Com's Answer #110238 by jojo14344(1513) ![]() You can put this solution on YOUR website! The answer is right, 160 minutes. \n" ); document.write( "We'll look how it arrived there. Rememeber the following, \n" ); document.write( "Rate of \n" ); document.write( "Rate of \n" ); document.write( "Pipe \n" ); document.write( "Pipe \n" ); document.write( ". \n" ); document.write( "It took \n" ); document.write( " \n" ); document.write( "x=25L (remaining volume to fill) \n" ); document.write( "It just makes sense, only half of the total time he used (100 min), so only half of the tank remains (25L). \n" ); document.write( "Now, to continue filling the remaining 25L, Pipe B joins the process. \n" ); document.write( "We need to add the rate of Pipe A + Rate of Pipe B for the remining task: \n" ); document.write( " \n" ); document.write( "Then, \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "In conclusion, we add this 60 minutes (Both A & B) + 100 minutes (alone Pipe A)= 160 minutes \n" ); document.write( "Thank you, \n" ); document.write( "Jojo \n" ); document.write( " \n" ); document.write( " |