document.write( "Question 150241: Pipe A fills a 50-liter tank at a rate of 15 liters per hour. Pipe B fills the same tank at a rate of 10 liters per hour. Pipe A runs alone for 100 minutes then the two of them together finish filling up the tank. How long does the whole operation take?\r
\n" ); document.write( "\n" ); document.write( "The answer is 160 minutes, but I have no idea how to arrive at this answer. Thank you!
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Algebra.Com's Answer #110238 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
The answer is right, 160 minutes.
\n" ); document.write( "We'll look how it arrived there. Rememeber the following,
\n" ); document.write( "Rate of \"A=15L%2Fhr\"
\n" ); document.write( "Rate of \"B=10L%2Fhr\"
\n" ); document.write( "Pipe \"A\"=\"50L%2F%2815L%2Fhr%29\"=3.333hrs=200 minutes it takes to fill the tank
\n" ); document.write( "Pipe \"B\"=\"50L%2F%2810L%2Fhr%29\"=5 hours= 300 minutes it takes to fill the tank
\n" ); document.write( ".
\n" ); document.write( "It took \"100+minutes\" for Pipe A alone to fill the tank at first. You see above, it needs 200 minutes for A to fill 50L tank. By ratio & proportion,
\n" ); document.write( "\"50L%2F200minutes=x%2F100minutes\"
\n" ); document.write( "x=25L (remaining volume to fill)
\n" ); document.write( "It just makes sense, only half of the total time he used (100 min), so only half of the tank remains (25L).
\n" ); document.write( "Now, to continue filling the remaining 25L, Pipe B joins the process.
\n" ); document.write( "We need to add the rate of Pipe A + Rate of Pipe B for the remining task:
\n" ); document.write( "\"%2815L%2Fhr%29%2B%2810L%2Fhr%29=25L%2Fhr\"
\n" ); document.write( "Then,
\n" ); document.write( "\"x=25L%2Fcombined+rate=25L%2F%2825L%2Fhr%29\"= 1 hour = 60 minutes
\n" ); document.write( ".
\n" ); document.write( "In conclusion, we add this 60 minutes (Both A & B) + 100 minutes (alone Pipe A)= 160 minutes
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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