document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=150204>Question 150204</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0536509344/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Hello,\r<BR>\n" );
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document.write( "I am helping my child with homework and i think i got the answer right but i am not sure please help.  thanks\r<BR>\n" );
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document.write( "Problem 1<BR>\n" );
document.write( " 5 5/9\r<BR>\n" );
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document.write( "+2 1/5<BR>\n" );
document.write( "_______\r<BR>\n" );
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document.write( "Problem 2<BR>\n" );
document.write( "3/5 + 1/3 T=2/5 <BR>\n" );
document.write( "The solution is T= (?) not sure of the answer\r<BR>\n" );
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document.write( "Thanks for your help \r<BR>\n" );
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document.write( "Marcia </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #110221 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=110221\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Problem 1<BR>\n" );
document.write( "5 5/9 <BR>\n" );
document.write( "+2 1/5<BR>\n" );
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document.write( "I assume you are asked to add these two numbers.<BR>\n" );
document.write( "They can be added when they have the same denominator:<BR>\n" );
document.write( "The least common denominator for 9 and 5 is 45.<BR>\n" );
document.write( "Rewrite each number using 45 as its denominator:<BR>\n" );
document.write( "5 5/9 = 5 25/45<BR>\n" );
document.write( "2 1/5 = 2 9/45<BR>\n" );
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document.write( "Adding you get 7 34/45<BR>\n" );
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document.write( "_______ <BR>\n" );
document.write( "Problem 2<BR>\n" );
document.write( "(3/5) + (1/3)T = (2/5)<BR>\n" );
document.write( "subtract (3/5) from both sides of the equation to get:<BR>\n" );
document.write( "(1/3)T = (-1/5)<BR>\n" );
document.write( "Multiply both sides to the equation by 3 to get:<BR>\n" );
document.write( "T = (-3/5)<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
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