document.write( "Question 150124: an executive invest $22000, some at 7% and some at6% annual interest. If he recieves an annual return of $1420, how much is invested in each rate? \n" ); document.write( "
Algebra.Com's Answer #110218 by checkley77(12844)\"\" \"About 
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.07X+.06(22,000-X)=1,420
\n" ); document.write( ".07X+1,320-.06X=1,420
\n" ); document.write( ".02X=1,420-1,320
\n" ); document.write( ".01X=100
\n" ); document.write( "X=100/.01
\n" ); document.write( "X=$10,000 INVESTED @ 7%.
\n" ); document.write( "22,000-10,000=$12,000 INVESTED @ 6%.
\n" ); document.write( "PROOF
\n" ); document.write( ".07*10,000+.06*12,000=1,420
\n" ); document.write( "700+720=1,420
\n" ); document.write( "1,420=1,420\r
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