document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=150187>Question 150187</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle yard is 290 ft. If its length is 25 feet greater than its width, what are the dimensions of the yard? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #110213 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=110213\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2L+2W<BR>\n" );
document.write( "290=2(W+25)+2W<BR>\n" );
document.write( "290=2W+50+2W<BR>\n" );
document.write( "290=4W+50<BR>\n" );
document.write( "4W=290-50<BR>\n" );
document.write( "4W=240<BR>\n" );
document.write( "W=240/4<BR>\n" );
document.write( "W=60 YARDS FOR THE WIDTH.<BR>\n" );
document.write( "L=60+25<BR>\n" );
document.write( "L=85 YARDS FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "290=2*85+2*60<BR>\n" );
document.write( "290=170+120<BR>\n" );
document.write( "290=290<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );