document.write( "Question 150114: Can you please help me solve this problem:\r
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document.write( "1.) A teacher is 15 years older than her student. In 15 years, the ratio of their ages will be 3:2. Find their present ages.\r
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Algebra.Com's Answer #110185 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=student's age; x+15=students age in 15 years \n" ); document.write( "Then x+15=teacher's age; x+30=teacher's age in 15 years\r \n" ); document.write( "\n" ); document.write( "Now we are told that: \n" ); document.write( "(x+30)/(x+15)=3/2 multiply each term by 2(x+15) or cross-multiply\r \n" ); document.write( "\n" ); document.write( "2(x+30)=3(x+15) get rid of parens (distributive law)\r \n" ); document.write( "\n" ); document.write( "2x+60=3x+45 subtract 60 and also 3x from each side\r \n" ); document.write( "\n" ); document.write( "2x-3x+60-60=3x-3x+45-60 collect like terms\r \n" ); document.write( "\n" ); document.write( "-x=-15 multiply each side by -1 \n" ); document.write( "x=15---------------------------student's age \n" ); document.write( "x+15=15+15=30------------------------teacher's age\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "(30+15)/(15+15)=3/2 \n" ); document.write( "45/30=3/2 \n" ); document.write( "3/2=3/2\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |