document.write( "Question 150103: A student claims that if a price is now 220% more than it was before, then it is 320% of what it was before, and what it was before is 31.25% of what it is now. Do you agree? Explain your answer.\r
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\n" ); document.write( "\n" ); document.write( "Im sorry, but i really don't get this question. =[
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Algebra.Com's Answer #110177 by kev82(151)\"\" \"About 
You can put this solution on YOUR website!
lets call the new price \"new_price\" and the old price \"old_price\". Let's look at the statements one by one\r
\n" ); document.write( "\n" ); document.write( "if a price is now 220% more than it was before\r
\n" ); document.write( "\n" ); document.write( "Percentages are always over 100, so 220% is 220/100 = 2.2. That's of the old price though, so it is \"2.2%2Aold_price\" more than the old price. So the new price is \"old_price+%2B+2.2%2Aold_price+=+3.2%2Aold_price\" 3.2 = 320/100 so the new price is 320% of the old price, yes.\r
\n" ); document.write( "\n" ); document.write( "and what it was before is 31.25% of what it is now\r
\n" ); document.write( "\n" ); document.write( "What is was before is \"old_price\", and what it is now is \"new_price\". To work out a percentage like this we divide the two things and times by 100. So what we need to do \"100%2Aold_price%2Fnew_price\". But we know that \"new_price=3.2%2Aold_price\" from above, we substitute and get \"%28100%2Aold_price%29%2F%283.2%2Aold_price%29\" There is an \"old_price\" on the top and bottom of this division, so it cancels to give 100/3.2 which is 31.25, so again the answer is yes.
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