document.write( "Question 22542: I really need help for this problem!\r
\n" ); document.write( "\n" ); document.write( "The capacity of an automobile cooling system is 16 quarts. It is half full of a 15% antifreeze solution. The owner is adding 2 gallons (another 8 qts.) of a 90% solution. When he is finished, what will the solution's percentage be?\r
\n" ); document.write( "\n" ); document.write( "Any help would be greatly appreciated!
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Algebra.Com's Answer #11017 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let x = the percentage of antifreeze in the 16 qts of coolant after the addition of the 8 qts of 90% solution. You can write the following equation after changing the percentages to their equvalent decimal values:\r
\n" ); document.write( "\n" ); document.write( "\"8%280.15%29+%2B+8%280.9%29+=+16%28x%29\" Simplify and solve for x.
\n" ); document.write( "\"8%281.05%29+=+16x\" Divide both sides by 16.
\n" ); document.write( "\"0.5%281.05%29+=+x\"
\n" ); document.write( "\"x+=+0.525\" Now change the decimal to a percent.
\n" ); document.write( "\"0.525+=+52.5\"%
\n" ); document.write( "The final solution will be 52.5% antifreeze.
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