document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=150080>Question 150080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Again will someone please help!<BR>\n" );
document.write( "Find the area of a triangle if side a = 3, and sides b and c = 2.<BR>\n" );
document.write( "Thanks again, Ray </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #110166 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=110166\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the area of a triangle if side a = 3, and sides b and c = 2.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Draw it with side a as the base.  Since sides b & c = 2, an altitude from vertex A makes to right triangles of equal area.<BR>\n" );
document.write( "Each right triangle has hypotenuse = 2 and base = 1.5<BR>\n" );
document.write( "Use Pythagoras to find the altitude, = sqrt (2^2 - 1.5^2)<BR>\n" );
document.write( "= sqrt(4-2.25)<BR>\n" );
document.write( "=sqrt(1.75)<BR>\n" );
document.write( "The area is bh/2, = 3*sqrt(1.75)/2<BR>\n" );
document.write( "= apx 1.9834 sq units </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );