document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=150090>Question 150090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solving the formula L=2d+pi(a+r) for a. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #110162 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=110162\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The idea is to isolate 'a' to one side of the equation -- doesn't matter which side.<BR>\n" );
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document.write( "L=2d+pi(a+r)<BR>\n" );
document.write( "Start by subtracting 2d from both sides to get:<BR>\n" );
document.write( "L-2d = pi(a+r)<BR>\n" );
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document.write( "Now, divide both sides by pi:<BR>\n" );
document.write( "(L-2d)/pi = a+r<BR>\n" );
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document.write( "Finally subtract r from both sides:<BR>\n" );
document.write( "((L-2d)/pi) - r = a<BR>\n" );
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