document.write( "Question 150053: x^2-3x+5=x(x-8)+20 \n" ); document.write( "
Algebra.Com's Answer #110147 by nerdybill(7384) You can put this solution on YOUR website! x^2-3x+5=x(x-8)+20 \n" ); document.write( "Start by distributing the 'x' to terms inside the parenthesis on the right: \n" ); document.write( "x^2-3x+5=x^2-8x+20 \n" ); document.write( "Subtracting x^2 from both sides leaves: \n" ); document.write( "-3x+5=-8x+20 \n" ); document.write( "Adding 8x to both sides gives us: \n" ); document.write( "5x+5=20 \n" ); document.write( "Subtracting 5 from both sides: \n" ); document.write( "5x=15 \n" ); document.write( "Finally dividing both sides by 5: \n" ); document.write( "x = 3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |