document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149984>Question 149984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help!<BR>\n" );
document.write( "If we establish an identity:<BR>\n" );
document.write( "(tan A - cot A)/(tan A + cot A) would equal what?\r<BR>\n" );
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document.write( "Thank you, Tami </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #110092 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=110092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying the numerator and denominator by sin(A)*cos(A) gives [sin^2(A)-cos^2(A)]/[sin^2(A)+cos^2(A)]\r<BR>\n" );
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document.write( "since sin^2(A)+cos^2(A)=1, we are left with sin^2(A)-cos^2(A) or 1-2cos^2(A) </SPAN>\n" );
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