document.write( "Question 149964: Cecile is now four times as old as Daisy.Five years ago, the sum of their ages was 45.How old is each now?\r
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Algebra.Com's Answer #110075 by Caxxx(4)![]() ![]() ![]() You can put this solution on YOUR website! let x- Daisy's age \n" ); document.write( "let y- Cecile's age \n" ); document.write( " x-5 Daisy's age 5 years ago \n" ); document.write( " y-5 Cecile's age 5 years ago \r \n" ); document.write( "\n" ); document.write( "(x-5)+(y-5)= 45 \n" ); document.write( "x-5+y-5= 45=5+5 \n" ); document.write( "x+y= 55 \n" ); document.write( "y= -x+55 -- equation 1\r \n" ); document.write( "\n" ); document.write( "Cecile is now four times as old as Daisy so, \n" ); document.write( " 4x=y --equation 2\r \n" ); document.write( "\n" ); document.write( "4x=y: Substitute y from equation 1 \n" ); document.write( "4x= -x+55 \n" ); document.write( "4x+x=55 \n" ); document.write( "5x= 55 \n" ); document.write( "Divide both sides by 5 to eliminate the numerical coefficient \n" ); document.write( "5x/5= 55/5 \n" ); document.write( "x= 11 \n" ); document.write( "Daisy is 11 years old.\r \n" ); document.write( "\n" ); document.write( "y=-x+55 \n" ); document.write( "since x is equal to eleven, so \n" ); document.write( "y= -11+55 \n" ); document.write( "y= 44 \n" ); document.write( "Cecile is 44 years old. \n" ); document.write( " \n" ); document.write( " |