document.write( "Question 149948: Find an equation of the line having the given slope and containing the given point. Express your answer in the form y=mx+b
\n" ); document.write( "m=-3 (5,0)
\n" ); document.write( "

Algebra.Com's Answer #110052 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"-3\" which goes through the point (\"5\",\"0\"), you can simply use the point-slope formula to find the equation:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-0=%28-3%29%28x-5%29\" Plug in \"m=-3\", \"x%5B1%5D=5\", and \"y%5B1%5D=0\" (these values are given)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-0=-3x%2B%28-3%29%28-5%29\" Distribute \"-3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y-0=-3x%2B15\" Multiply \"-3\" and \"-5\" to get \"15\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=-3x%2B15%2B0\" Add 0 to both sides to isolate y\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=-3x%2B15\" Combine like terms \"15\" and \"0\" to get \"15\" \r
\n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"-3\" which goes through the point (\"5\",\"0\") is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=-3x%2B15\" which is now in \"y=mx%2Bb\" form where the slope is \"m=-3\" and the y-intercept is \"b=15\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=-3x%2B15\" and plot the point (\"5\",\"0\"), we get (note: if you need help with graphing, check out this solver)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Graph of \"y=-3x%2B15\" through the point (\"5\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"-3\" and goes through the point (\"5\",\"0\"), this verifies our answer.
\n" ); document.write( "
\n" );