document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149944>Question 149944</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Working together, a painter and the painter's apprentice can paint a room in 4h. Working alone, the apprentice requires 7 more hours to paint the room that the painter requires working alone. How long does it take the painter, working alone, to paint the room? Please round your answer to one decimal place. \r<BR>\n" );
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document.write( "4/T + 4/T+7 = 1<BR>\n" );
document.write( "T(T+7)(4/T + 4/T+7) = T(T+7)1<BR>\n" );
document.write( "(T+7)4+4T = T(T+7)<BR>\n" );
document.write( "4T +28 +4T = T^2 +T7<BR>\n" );
document.write( "8T+28=T^2+T7\r<BR>\n" );
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document.write( "Am I doing this right? I keep coming up with the wrong answer, I think. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #110048 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=110048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> subtracting 8T+28 __ 0=T^2-T-28\r<BR>\n" );
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document.write( "using quadratic formula __ T=[1ħsqrt(1-(4*1*(-28)))]/2 __ T=[1ħsqrt(113)]/2\r<BR>\n" );
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document.write( "T=5.82 (approx) </SPAN>\n" );
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