document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149896>Question 149896</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321233832/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular garden has dimensions of 18 ft by 13 ft. A gravel path of uniform width is to be built around the garden. How wide can the path be if there is enough gravel for 516 square feet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #110026 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=110026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 18*13=234 ft^2 for the garden.<BR>\n" );
document.write( "234+516=750 is the area for the garden plus the path.<BR>\n" );
document.write( "(18+2x)(13+2x)=750<BR>\n" );
document.write( "234+36x+26x+4x^2=750<BR>\n" );
document.write( "4x^2+62x+234-750=0<BR>\n" );
document.write( "4x^2+62x-516=0<BR>\n" );
document.write( "2(2x^2+31x-258)=0<BR>\n" );
document.write( "2(2x+43)(x-6)=0<BR>\n" );
document.write( "x-6=0<BR>\n" );
document.write( "x=6 for the width of the path.<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( "(18+2*6)(13+2*6)+750<BR>\n" );
document.write( "(18+12)(13+12)=750<BR>\n" );
document.write( "30*25=750<BR>\n" );
document.write( "750=750<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );