document.write( "Question 149897This question is from textbook
\n" ); document.write( ": Steve traveled 200 miles at a certain speed. Had he gone 10mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle. \n" ); document.write( "
Algebra.Com's Answer #110002 by mangopeeler07(462)\"\" \"About 
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x=speed
\n" ); document.write( "y=time\r
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\n" ); document.write( "\n" ); document.write( "200/x=y
\n" ); document.write( "200/x+10=y-1\r
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\n" ); document.write( "\n" ); document.write( "Plug in y in the second equation
\n" ); document.write( "(200/x+10)=(200/x)-1\r
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\n" ); document.write( "\n" ); document.write( "Common denominator=\"x%5E2%2B10x\"
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\n" ); document.write( "\n" ); document.write( "Subtract on the right
\n" ); document.write( "\"%28200x%2F%28x%5E2%2B10x%29%29=%28%28200x-2000-x%5E2-10%29%2F%28x%5E2%2B10x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Eliminate the denominator.
\n" ); document.write( "Subtract 200x from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"0=2000-x%5E2-10x\"\r
\n" ); document.write( "\n" ); document.write( "Reorder the right side
\n" ); document.write( "\"0=-x%5E2-10x%2B2000\"\r
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\n" ); document.write( "\n" ); document.write( "Take out a ngeative one
\n" ); document.write( "\"0=-1%28x%5E2%2B10x-2000%29\"\r
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\n" ); document.write( "\n" ); document.write( "Factor
\n" ); document.write( "\"0=-1%28x%2B50%29%28x-40%29\"\r
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\n" ); document.write( "\n" ); document.write( "Solve
\n" ); document.write( "x=-50
\n" ); document.write( "x=40\r
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\n" ); document.write( "\n" ); document.write( "since speed can't be negative, x=40, so\r
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\n" ); document.write( "\n" ); document.write( "40 mph
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