document.write( "Question 149859: Three years ago, a man was eight times as old as his son. In two years, he will be four times as old as the son. Find their present ages. \r
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Algebra.Com's Answer #109999 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! man=m \n" ); document.write( "son=s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "m-3=8(s-3) \n" ); document.write( "m+2=4(s+2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for m in the first equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "m=8(s-3)+3 \n" ); document.write( "Distribute \n" ); document.write( "m=8s-24+3 \n" ); document.write( "m=8s-21\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug that into the second equation \n" ); document.write( "8s-21+2=4(s+2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distribute the 4 \n" ); document.write( "8s-21+2=4s+8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Combine like terms \n" ); document.write( "8s-19=4s+8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 19 to both sides \n" ); document.write( "8s=4s+27\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 4s from both sides \n" ); document.write( "4s=27\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide by 4 \n" ); document.write( "s=27/4 0r 6 and 3/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "m-3=8(s-3) \n" ); document.write( "m-3=8(27/4-3) \n" ); document.write( "m-3=54-24 \n" ); document.write( "m-3=30 \n" ); document.write( "m=33\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "son=6 years and 9 months \n" ); document.write( "man=33 years \n" ); document.write( " |