document.write( "Question 149859: Three years ago, a man was eight times as old as his son. In two years, he will be four times as old as the son. Find their present ages. \r
\n" ); document.write( "\n" ); document.write( "Thank you.
\n" ); document.write( "

Algebra.Com's Answer #109999 by mangopeeler07(462)\"\" \"About 
You can put this solution on YOUR website!
man=m
\n" ); document.write( "son=s\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "m-3=8(s-3)
\n" ); document.write( "m+2=4(s+2)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve for m in the first equation\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "m=8(s-3)+3
\n" ); document.write( "Distribute
\n" ); document.write( "m=8s-24+3
\n" ); document.write( "m=8s-21\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Plug that into the second equation
\n" ); document.write( "8s-21+2=4(s+2)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Distribute the 4
\n" ); document.write( "8s-21+2=4s+8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Combine like terms
\n" ); document.write( "8s-19=4s+8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Add 19 to both sides
\n" ); document.write( "8s=4s+27\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Subtract 4s from both sides
\n" ); document.write( "4s=27\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Divide by 4
\n" ); document.write( "s=27/4 0r 6 and 3/4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "m-3=8(s-3)
\n" ); document.write( "m-3=8(27/4-3)
\n" ); document.write( "m-3=54-24
\n" ); document.write( "m-3=30
\n" ); document.write( "m=33\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "son=6 years and 9 months
\n" ); document.write( "man=33 years
\n" ); document.write( "
\n" );