document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149821>Question 149821</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The period T(time in seconds for one complete cycle) of a simple pendulum is realated to length L (in feet)of the pendulum for the formula 8T^2 = PIE^2L. If a child is on a swing with a 10- foot chain, then how long does it take to complete on cycle of the swing?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109938 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109938\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The period T(time in seconds for one complete cycle) of a simple pendulum is related to length L (in feet) of the pendulum for the formula 8T^2 = PIE^2L. <BR>\n" );
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document.write( "If a child is on a swing with a 10-foot chain, then how long does it take to complete on cycle of the swing? <BR>\n" );
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document.write( "8T^2 = (pi)^(2*10)<BR>\n" );
document.write( "8T^2 = 62.83...<BR>\n" );
document.write( "T = sqrt[62.83/8] = 2.8 seconds<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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