document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22577>Question 22577</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If y varies directly as x and y=8 when x=3 find y when x=5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10992 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y varies directly as x means the following:<BR>\n" );
document.write( "y= kx where \"k\" is a number we have to find.<BR>\n" );
document.write( "Since y=8 when x=3 we get the following equation<BR>\n" );
document.write( "which allows us to solve for \"k\": 8=k(3)<BR>\n" );
document.write( "Therefore k=8/3<BR>\n" );
document.write( "Now we know the general formula is y=(8/3)x<BR>\n" );
document.write( "So, if x=5 y=(8/3)(5) = 40/3\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );