document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149779>Question 149779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tammy wants to complete a jigsaw puzzle. On the first day, she manages to fit 20% of the puzzle. On the second day, she fits another 60 pieces of the puzzle. As a result, the ratio of the number of fitted pieces to the number of unfitted pieces becomes 2:5. How many pieces does the jigsaw puzzle consist?\r<BR>\n" );
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document.write( "Rmks: Pls try not to use algebra. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109910 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = number of pieces in the puzzle<BR>\n" );
document.write( ".20x + 60 = pieces fitted on second day<BR>\n" );
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document.write( "From: \"the ratio of the number of fitted pieces to the number of unfitted pieces becomes 2:5\" we have:<BR>\n" );
document.write( "(.20x + 60)/(x-(.20x + 60)) = 2/5<BR>\n" );
document.write( "(.20x + 60)/(x-.20x - 60) = 2/5<BR>\n" );
document.write( "(.20x + 60)/(.80x - 60) = 2/5<BR>\n" );
document.write( "5(.20x + 60) = 2(.80x - 60)<BR>\n" );
document.write( "x + 300 = 1.6x - 120<BR>\n" );
document.write( "420 = .6x<BR>\n" );
document.write( "700 = x\r<BR>\n" );
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