document.write( "Question 149785: 60% of the area of Rectangle A is the same as 80% of the area of Rectangle B. Rectangle B is 25cm2 smaller than Rectangle A. Given that they both have a length of 25 cm, find the difference in their perimeter.\r
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document.write( "Rmks: Pls try not to use algebra. \n" );
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Algebra.Com's Answer #109898 by kmcruz09(38) ![]() You can put this solution on YOUR website! I don't think you can solve this one without using algebra. Anways, here's the solution.\r \n" ); document.write( "\n" ); document.write( "60% of the area of Rectangle A is the same as 80% of the area of Rectangle B. Rectangle B is 25cm2 smaller than Rectangle A. Given that they both have a length of 25 cm, find the difference in their perimeter.\r \n" ); document.write( "\n" ); document.write( "let x = width of rectangle A \n" ); document.write( "let y = width of rectangle B\r \n" ); document.write( "\n" ); document.write( "then Area of rectangle A = 25x \n" ); document.write( "and Area of rectangle B = 25y\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "PERIMETERa = \n" ); document.write( "= \n" ); document.write( "PERIMETERb = \n" ); document.write( "= \n" ); document.write( "\n" ); document.write( "PERIMETERa - PERIMETERb = 2cm \n" ); document.write( " |