document.write( "Question 149677: Lucy has invested some money invested at 18% and three times as much invested at 12%. her total annual income from the 2 investment is 85,000 pesos. how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #109881 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .18x+.12*3x=85,000 \n" ); document.write( ".18x+.36x=85,000 \n" ); document.write( ".54x=85,000 \n" ); document.write( "x=85,000/.54 \n" ); document.write( "x=157,407.40 invested @ 18% \n" ); document.write( "3*157,407.40=472,222.20 invested @ 12% \n" ); document.write( "proof: \n" ); document.write( ".18*157,407.40+.12*472,222.20=85,000 \n" ); document.write( "28,333.33+56,666.67=85,000 \n" ); document.write( "85,000=85,000 \n" ); document.write( " |