document.write( "Question 149760: If a bowling ball is 8 inches in diameter, what is it's volume to the nearest cubic inch ?\r
\n" ); document.write( "\n" ); document.write( "Formula : V= 4/3 (3.14)R3 ----- THAT IS \"V\" equals pie times r to the 3rd power\r
\n" ); document.write( "\n" ); document.write( "I have never worked with any problems like this and just really wanted to see someone work it out ! \n" ); document.write( "
Algebra.Com's Answer #109870 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
The problem gives you the volume of a sphere:
\n" ); document.write( "V= 4/3 (3.14)R^3
\n" ); document.write( "where
\n" ); document.write( "V is the volume
\n" ); document.write( "R is the radius
\n" ); document.write( ".
\n" ); document.write( "Also, in the problem, they said that the bowling ball is 8 inches in diameter.
\n" ); document.write( "Since, half the diameter is the radius we have:
\n" ); document.write( "R = (1/2)(8)= 4 inches
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\n" ); document.write( "Now we simply plug it into our equation:
\n" ); document.write( "V= 4/3 (3.14)(4)^3
\n" ); document.write( "First, multiplying the 4 and 3.14 we get:
\n" ); document.write( "V= (12.56/3)(4)^3
\n" ); document.write( "Dividing 12.56 by 3:
\n" ); document.write( "V= (4.187)(4)^3
\n" ); document.write( "Then we resolve 4^3:
\n" ); document.write( "V= (4.187)(64)
\n" ); document.write( "Finally, we get:
\n" ); document.write( "V= 267.947 cubic inches\r
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