document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149761>Question 149761</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please can someone help me with this problem: For i= -1, 3i(2+5i)= x+6i,then x=?<BR>\n" );
document.write( "This is how i tried to solve the problem: 3ix2=6i,and 3ix5i=15i,now i combine 6i+ 15i = x + 6i, I broke down the problem by adding 6i + 15i=  21i=x+6i, then i made the 21i negative on both sides:<BR>\n" );
document.write( " 21i = x + 6i<BR>\n" );
document.write( "-21i     -21i= -15, is this correct?<BR>\n" );
document.write( "           </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109868 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3i(2+5i)= x+6i,then x=?<BR>\n" );
document.write( ";<BR>\n" );
document.write( "Not quite: 3i * 5i = 15i^2; we know i^2 = -1. so we have:<BR>\n" );
document.write( "6i + 15i^2 = x + 6i<BR>\n" );
document.write( ":<BR>\n" );
document.write( "6i + 15(-1) = x + 6i<BR>\n" );
document.write( "which is:<BR>\n" );
document.write( "6i - 15 = x + 6i<BR>\n" );
document.write( ":<BR>\n" );
document.write( "6i - 6i - 15 = x<BR>\n" );
document.write( ":<BR>\n" );
document.write( "x = -15<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Actually much simpler than you made it to be:<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );