document.write( "Question 149766: Find the quotient of \"x%5E5%2B32\" divided by \"x%2B2\" \n" ); document.write( "
Algebra.Com's Answer #109865 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's simplify this expression using synthetic division\r
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\n" ); document.write( "\n" ); document.write( "Start with the given expression \"%28x%5E5+%2B+32%29%2F%28x%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "First lets find our test zero:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2=0\" Set the denominator \"x%2B2\" equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2\" Solve for x.\r
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\n" ); document.write( "\n" ); document.write( "so our test zero is -2\r
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\n" ); document.write( "\n" ); document.write( "Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.(note: remember if a polynomial goes from \"x%5E5\" to \"32\" there is a zero coefficient for \"x%5E4\", \"x%5E3\", \"x%5E2\", and \"x\". This is simply because \"x%5E5+%2B+32\" really looks like \"1x%5E5%2B0x%5E4%2B0x%5E3%2B0x%5E2%2B0x%5E1%2B32x%5E0\"\n" ); document.write( "\n" ); document.write( "
-2|1000032
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\r
\n" ); document.write( "\n" ); document.write( "Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 1)\r
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-2|1000032
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1
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\n" ); document.write( "\n" ); document.write( " Multiply -2 by 1 and place the product (which is -2) right underneath the second coefficient (which is 0)\r
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-2|1000032
|-2
1
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\n" ); document.write( "\n" ); document.write( " Add -2 and 0 to get -2. Place the sum right underneath -2.\r
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-2|1000032
|-2
1-2
\r
\n" ); document.write( "\n" ); document.write( " Multiply -2 by -2 and place the product (which is 4) right underneath the third coefficient (which is 0)\r
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-2|1000032
|-24
1-2
\r
\n" ); document.write( "\n" ); document.write( " Add 4 and 0 to get 4. Place the sum right underneath 4.\r
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-2|1000032
|-24
1-24
\r
\n" ); document.write( "\n" ); document.write( " Multiply -2 by 4 and place the product (which is -8) right underneath the fourth coefficient (which is 0)\r
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-2|1000032
|-24-8
1-24
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\n" ); document.write( "\n" ); document.write( " Add -8 and 0 to get -8. Place the sum right underneath -8.\r
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-2|1000032
|-24-8
1-24-8
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\n" ); document.write( "\n" ); document.write( " Multiply -2 by -8 and place the product (which is 16) right underneath the fifth coefficient (which is 0)\r
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-2|1000032
|-24-816
1-24-8
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\n" ); document.write( "\n" ); document.write( " Add 16 and 0 to get 16. Place the sum right underneath 16.\r
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-2|1000032
|-24-816
1-24-816
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\n" ); document.write( "\n" ); document.write( " Multiply -2 by 16 and place the product (which is -32) right underneath the sixth coefficient (which is 32)\r
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-2|1000032
|-24-816-32
1-24-816
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\n" ); document.write( "\n" ); document.write( " Add -32 and 32 to get 0. Place the sum right underneath -32.\r
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-2|1000032
|-24-816-32
1-24-8160
\r
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\n" ); document.write( "\n" ); document.write( "Since the last column adds to zero, we have a remainder of zero. This means \"x%2B2\" is a factor of \"x%5E5+%2B+32\"\r
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\n" ); document.write( "\n" ); document.write( "Now lets look at the bottom row of coefficients:\r
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\n" ); document.write( "\n" ); document.write( "The first 5 coefficients (1,-2,4,-8,16) form the quotient\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E4+-+2x%5E3+%2B+4x%5E2+-+8x+%2B+16\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"%28x%5E5+%2B+32%29%2F%28x%2B2%29=x%5E4+-+2x%5E3+%2B+4x%5E2+-+8x+%2B+16\" which means that the quotient is \"x%5E4+-+2x%5E3+%2B+4x%5E2+-+8x+%2B+16\" and the remainder is 0.\r
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