document.write( "Question 149721: Find the exact value of cot(-pie/6) \n" ); document.write( "
Algebra.Com's Answer #109860 by jim_thompson5910(35256)\"\" \"About 
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\"cot%28-pi%2F6%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Ftan%28-pi%2F6%29\" Rewrite the cotangent in terms of tangent.\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%28-tan%28pi%2F6%29%29\" Use the identity \"tan%28-u%29=-tan%28u%29\" to rewrite the expression.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%2Ftan%28pi%2F6%29\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%2F%28%28sin%28pi%2F6%29%29%2F%28cos%28pi%2F6%29%29%29\" Rewrite the tangent function in terms of sine and cosine.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28cos%28pi%2F6%29%2Fsin%28pi%2F6%29%29\" Multiply -1 by the reciprocal of the dividing fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"-cos%28pi%2F6%29%2Fsin%28pi%2F6%29\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "Now, let's reference the unit circle\r
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\n" ); document.write( "\n" ); document.write( "From the unit circle, we can see that at the angle \"pi%2F6\", there is a point on the unit circle . So this tells us that \"cos%28pi%2F6%29=sqrt%283%29%2F2\" and \"sin%28pi%2F6%29=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "So this means that \"-cos%28pi%2F6%29%2Fsin%28pi%2F6%29\" then becomes \"-%28sqrt%283%29%2F2%29%2F%281%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-%28sqrt%283%29%2F2%29%2A%282%2F1%29\" Multiply the first fraction by the reciprocal of the second fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"-%28sqrt%283%29%2Fcross%282%29%29%2A%28cross%282%29%2F1%29\" Cancel like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-sqrt%283%29\" Multiply and simplify.\r
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\n" ); document.write( "\n" ); document.write( "So \"cot%28-pi%2F6%29=-sqrt%283%29\"
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