document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149650>Question 149650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve x= Arc tan(-squareroot 3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109791 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve x= Arc tan(-squareroot 3)<BR>\n" );
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document.write( "Find the arctan of sqrt(3) on a calculator<BR>\n" );
document.write( "= 60 degrees<BR>\n" );
document.write( "The tangent function goes +, -, +, - as you move from the 1st quadrant CCW, so it's -60 degs or 120 degs. </SPAN>\n" );
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