document.write( "Question 149606: a contractor has a 24-pound mixture that is no-fourth cement, and three-fourths sand. How much of a mixture that is half cement and half sand needs to be added to produce a mixture that is one-third cement? \n" ); document.write( "
Algebra.Com's Answer #109783 by ankor@dixie-net.com(22740)\"\" \"About 
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a contractor has a 24-pound mixture that is no-fourth cement, and three-fourths sand. How much of a mixture that is half cement and half sand needs to be added to produce a mixture that is one-third cement?
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\n" ); document.write( "We can write an equation based on the amt of cement
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\n" ); document.write( "Let x = amt of half cement mixture required
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\n" ); document.write( "\"1%2F4\"(24) + \"1%2F2\"x = \"1%2F3\"(x+24)
\n" ); document.write( "Multiply equation by 12 to get rid of the denominators
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\n" ); document.write( "3(24) + 6x = 4(x+24)
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\n" ); document.write( "72 + 6x = 4x + 96
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\n" ); document.write( "6x - 4x = 96 - 72
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\n" ); document.write( "2x = 24
\n" ); document.write( "x = \"24%2F2\"
\n" ); document.write( "x = 12 lb of the half cement mixture
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\n" ); document.write( "we can check solution base on the amt of sand:
\n" ); document.write( "\"3%2F4\"(24) + \"1%2F2\"(12) = \"2%2F3\"(12+24)
\n" ); document.write( "18 + 6 = \"2%2F3\"*36 \n" ); document.write( "
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