document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=149609>Question 149609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you solve: log(base 2x)+log(base 4x)+log(base 8x) = 1? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109751 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(base2) x+log(base4) x + log(base8) x = 1\r<BR>\n" );
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document.write( "[logx/log2] + [logx/2log2] + [logx/3log2] = 1\r<BR>\n" );
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document.write( "Multiply thru by 6log2 to get:\r<BR>\n" );
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document.write( "6logx + 3logx + 2logx = 6log2<BR>\n" );
document.write( "11logx = 6log2<BR>\n" );
document.write( "[logx/log2] = 6/11<BR>\n" );
document.write( "log(base2) x = 6/11<BR>\n" );
document.write( "x = 2^(6/11)<BR>\n" );
document.write( "x = 1.45948...<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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