document.write( "Question 149590: Simplify the expression 12x+10 over 2 \n" ); document.write( "

Algebra.Com's Answer #109744 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
= $\"%2812x%2B10%29%2F2\"$ becomes,
\n" ); document.write( " $\"%2812x%2F2%29+%2B+%2810%2F2%29+=+0\"$ ---------> working eqn
\n" ); document.write( "further simplifying,
\n" ); document.write( " $\"12x%2F2+%2B+5+=+0\"$
\n" ); document.write( " $\"12x%2F2=-5\"$
\n" ); document.write( " $\"-10=12x\"$
\n" ); document.write( " $\"x=+%28-5%2F6%29\"$ --------------> final answer
\n" ); document.write( "To check, go back working eqn & substitute the value of \"x\",
\n" ); document.write( " $\"%28%2812%29%28-5%2F6%29%29%2F2+%2B+10%2F2+=+0\"$
\n" ); document.write( " $\"%28-60%2F6%29%2F2+%2B+10%2F2+=+0+\"$
\n" ); document.write( " $\"+cross%28-10%2F2%29+%2B+cross%2810%2F2%29+=+0\"$
\n" ); document.write( " $\"0=0\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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