document.write( "Question 149566: The patel manufacturing company allows for a defect rate of 0.9% on its production line.The defect average for last week was 3 times out of 1,500.What is the difference between the allowed defect rate and the average for last week? \n" ); document.write( "
Algebra.Com's Answer #109726 by Fombitz(32388)\"\" \"About 
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\"3%2F1500=0.002\"
\n" ); document.write( "In terms of percentage that would be,
\n" ); document.write( "\"0.002=0.2%2F100\" or 0.2%.
\n" ); document.write( "The difference is
\n" ); document.write( "\"D=0.9-0.2=0.7\" or 0.7% better than average.
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