document.write( "Question 149544: Steve traveled 200 miles at a certain speed. Had he gone 10mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle. \n" ); document.write( "
Algebra.Com's Answer #109714 by mangopeeler07(462)\"\" \"About 
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200 miles
\n" ); document.write( "x speed
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\n" ); document.write( "\n" ); document.write( "200/x=y\r
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\n" ); document.write( "\n" ); document.write( "200/(x+10)=y-1\r
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\n" ); document.write( "\n" ); document.write( "Plug in y in the second equation
\n" ); document.write( "200/(x+10)=200/x-1\r
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\n" ); document.write( "\n" ); document.write( "Common denominator on the right side x
\n" ); document.write( "200/(x+10)=200/x-x/x\r
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\n" ); document.write( "\n" ); document.write( "Subtract the numerators
\n" ); document.write( "200/(x+10)=(200-x)/x\r
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\n" ); document.write( "\n" ); document.write( "Cross multiply
\n" ); document.write( "200x=-x^2+190x+2000\r
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\n" ); document.write( "\n" ); document.write( "Subtract 200x from both sides
\n" ); document.write( "0=-x^2-10x+2000\r
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\n" ); document.write( "\n" ); document.write( "Take out negative one
\n" ); document.write( "0=-1(x^2+10x-2000)\r
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\n" ); document.write( "\n" ); document.write( "Factor
\n" ); document.write( "0=-1(x+50)(x-40)\r
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\n" ); document.write( "\n" ); document.write( "Set each equal to zero and solve
\n" ); document.write( "(x+50)=0
\n" ); document.write( "x=-50\r
\n" ); document.write( "\n" ); document.write( "(x-40)=0
\n" ); document.write( "x=40\r
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\n" ); document.write( "\n" ); document.write( "Speed can't be negative, so x=40.\r
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\n" ); document.write( "\n" ); document.write( "Original speed: 40 mph
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