document.write( "Question 149525: Gian and Arwin can finish a project in 4 2/3 hours. Gian can do it alone in half as much as time arvin can do the job. how long will it take arwin to do the job alone. \n" ); document.write( "
Algebra.Com's Answer #109712 by ptaylor(2198)\"\" \"About 
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Let x=rate (projects per hour) at which Arvin works
\n" ); document.write( "Then 2x=rate at which Gian works (works twice as fast)
\n" ); document.write( "Together they work at the rate of x+2x=3x projects per hour\r
\n" ); document.write( "\n" ); document.write( "But we are told that together, they work at the rate of 1/(4 2/3) projects per hour= 3/14 projects per hour. So our equation to solve is:
\n" ); document.write( "3x=3/14 divide each side by 3
\n" ); document.write( "x=1/14 project per hour----------------rate at which Arvin works
\n" ); document.write( "Now if z=amount of time it takes Arvin to do the project, then
\n" ); document.write( "(1/14)*z=1 (1 project, that is)
\n" ); document.write( "z=14 hours---------------amount of time it takes Arvin working alone
\n" ); document.write( "Also:
\n" ); document.write( "2x=2(1/14)=2/14 projects per hour-------------------rate at which Gian works\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "1/14 + 2/14=1/(4 2/3)=1/(14/3)=3/14
\n" ); document.write( "3/14=3/14\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "
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