document.write( "Question 149528: there is an error in this problem... can you tell me where it is?? =\
\n" ); document.write( "x=2
\n" ); document.write( "x(x-1) = 2(x-1)
\n" ); document.write( "x^2-x = 2x-2
\n" ); document.write( "x^2-2x = x-2
\n" ); document.write( "x(x-2) = x-2
\n" ); document.write( "x=1\r
\n" ); document.write( "\n" ); document.write( "Thanks for you help.... jj
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Algebra.Com's Answer #109706 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
It's the second to last step. The error that occurs is a division by zero. \r
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\n" ); document.write( "\n" ); document.write( "If x=2, then x-2 is really 2-2=0\r
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\n" ); document.write( "\n" ); document.write( "So \"x-2=0\"\r
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\n" ); document.write( "\n" ); document.write( "So \"x%28x-2%29=x-2\" is really \"x%280%29=0\". \r
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\n" ); document.write( "\n" ); document.write( "In this step, there is a division by \"x-2\" to get \"x%28x-2%29%2F%28x-2%29=%28x-2%29%2F%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "However, since \"x-2=0\", this means that this happens \"x%280%29%2F%280%29=%280%29%2F%280%29\"\r
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\n" ); document.write( "\n" ); document.write( "But you cannot divide by zero. So this is where the flaw occurs. This is a common fallacy in the \"proofs\" of odd statements like 1=2 or 0=1. Or in this case, you're \"proving\" that x=1=2.
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